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遵循着共同的规律的多变元n+1≥2曲函数

万金华 (wjh68389653hjw@sina.com) 上传2007.06 浏览172


“低维与高维统一、非轮回与轮回统一、 低值与高值统一、数矩阵与指数矩阵统一、 (+1)开n次方与n×n阶正斜轮回单位 矩阵开n次方的统一”、 引起“低曲函数与多曲函数统一、 实数与超实数统一、数与矩阵统一”、 用正斜轮回矩阵把单变元“双曲函数”推广 为单变元和多变元“n+1≥3”曲函数, 使得各曲函数均遵循着共同的规律:

多变元n+1≥2曲函数:

Bn(T)=exp(Jnrtr

=〖Sn,0(T)n,Sn,n-1(T)…,Sn,1(T)〗

JnkSn,k((T)

T=(t1,t2,…,tn-1

Sn,k(T)=Sn,k(t1,t2,…,tn-1)=

∑(tjpj)/(pj!))

Pr=q,Pr≥0(r=1,2,…,n-1),rpr≡k(mod n)

这“多变元n+1≥2曲函数”同样满足“双曲函数”

和“单变量n+1≥2曲函数”的所有规律:

1、万氏欧拉公式:

exp(Jnrtr)=JnkSn,k((T)

2、万氏棣美弗公式:

JnkSn,k((T))αJnkSn,k((αT)

3、万氏和角公式:
(Sn,0(α+β),Sn,1(α+β),…,Sn,n-1(α+β))-1Bn(α)(Sn,0(β),Sn,1(β),…,Sn,n-1(β))-1Bn(β)(Sn,0(α),Sn,1(α),…,Sn,n-1(α))-1
(Sn,0(α+β),Sn,1(α+β),…,Sn,n-1(α+β)) =(Sn,0(α),Sn,1(α),…,Sn,n-1(α))Bn(β) =(Sn,0(β),Sn,1(β),…,Sn,n-1(β))Bn(α)

4、万氏倍元公式:
(Sn,0(αT),Sn,1(αT),…,S,n-1(αT))-1Bnα-1(T)(Sn,0(T),Sn,1(T),…,Sn,n-1(T))-1
(Sn,0(αT),Sn,1(αT),…,Sn,n-1(αT)) =(Sn,0(T),Sn,1(T),…,Sn,n-1(T))Bnα-1(T)

5、万氏双曲型行列式为1公式:
Bn(T)| =|exp(Jnrtr)| =|〖Sn,0(T)n,S,n-1(T)…,Sn,1(T)〗| =1, n×n阶行列式值为1

当n=2时即此行列式展开即为双曲函数的公式:Ch2t-Sh2t=1

6、万氏循环导数公式:
Sn,k(T)/tj=sn,k-j(t),当k-j≥0时;
Sn,k(t)/tj=sn,n+k-j(t),当k-j<0时

7、万氏有限欧拉公式:
虚数型公式: Sn,k(T)=Sn,k,1(T)+iSn,k,2(t)=Sn,k,1(T)= =n-1(-1)(n+1)kexp((-1)(n+1)rtrexp(2βriπ/n)-2βkiπ/n)
实数型(正好是上式的实部)公式: Sn,k(T)=Sn,k,1(T)= =n-1(-1)(n+1)kexp((-1)(n+1)rtrCOS(2βrπ/n))COS(Fβ
故有恒等式: Sn,k,2(T)=exp((-1)(n+1)rtrCOS(2βrπ/n))SIN(Fβ)=0
其中 Fβ(-1)(n+1)rtrSIN(2βrπ/n)-2βkπ/n
Sn,k(T)=exp(tr),

8、万氏有限和公式:
Sn,k(T)=exp(tr),
(-1)(n+1)kSn,k(T)=exp((-1)(n+1)rtr

9、特殊例子:

①、n=2对为“一元双曲函数”即普通“双曲函数”:
S2,0(t1)=(et1+e-t1)/2=Cht1 S2,1(t1)=(et1-e-t1)/2=Cht1

②、n=3对为“二元叁曲函数”:
S3,0(t1,t2) =(exp(t1+t2) +2exp((-t1-t2)/2)COS((t1-t2)/2))/3
S3,1(t1,t2) =-(exp(t1+t2) +2exp((-t1-t2)/2)COS((t1-t2)/2+2π/3))/3
R3,2(t1,t2) =(exp(t1+t2) +2exp((-t1-t2)/2)COS((t1-t2)/2-2π/3))/3

③、n=4为“三元肆曲函数”:
S4,0(t1,t2,t3) =(exp(-t1+t2-t3)+exp(t2)COS(-t1+t3)+exp(t1+t2+t3) +exp(-t2)COS(t1-t3))/4
S4,1(t1,t2,t3) =(-exp(-t1+t2-t3)-exp(t2)SIN(-t1+t3)+exp(t1+t2+t3) +exp(-t2)COS(t1-t3))/4
S4,2(t1,t2,t3) =(exp(-t1+t2-t3)-exp(t2)COS(-t1+t3)+exp(t1+t2+t3) -exp(-t2)COS(t1-t3))/4
S4,3(t1,t2,t3) =(-exp(-t1+t2-t3)+exp(t2)SIN(-t1+t3)+exp(t1+t2+t3) -exp(-t2)COS(t1-t3))/4

④、n=5时为“四元五曲函数”:
S5,0(t1,t2,t3,t4) =[exp(t1+t2+t3+t4)+2exp(T1)COS(T2) +2exp(T3)COS(T4)]/5
S5,1(t1,t2,t3,t4) =[exp(t1+t2+t3+t4)+2exp(T1)COS(T2-2π/5) +2exp(T3)COS(T4-4π/5)]/5
S5,2(t1,t2,t3,t4) =[exp(t1+t2+t3+t4)+2exp(T1)COS(T2-4π/5) +2exp(T3)COS(T4+2π/5)]/5
S5,3(t1,t2,t3,t4) =[exp(t1+t2+t3+t4)+2exp(T1)COS(T2+4π/5) +2exp(T3)COS(T4-2π/5)]/5
S5,4(t1,t2,t3,t4) =[exp(t1+t2+t3+t4)+2exp(T1)COS(T2+2π/5) +2exp(T3)COS(T4+4π/5)]/5

⑤n=5时为“五元陆曲函数”:
S6,0(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4)+2eT5COS(T6)]/6 =[exp(-t1+t2-t3+t4-t5)+exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2) +2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)/2)]/6
S6,1(t1,t2,t3,t4,t5) =[eT1-eT2+2eT3COS(T4+2π/3)+2eT5COS(T6)π/3]/6 =[exp(-t1+t2-t3+t4-t5)-exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2 +2π/3)+2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)/2 +π/3)]/6
S6,2(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4-2π/3)+2eT5COS(T6+2π/3)]/6 =[exp(-t1+t2-t3+t4-t5)+exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2-2π/3) +2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)z+2π/3)]/6
S6,3(t1,t2,t3,t4,t5) =[eT1-eT2+2eT3COS(T4)-2eT5COS(T6)]/6 =[exp(-t1+t2-t3+t4-t5)-exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2) -2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)/2)]/6
S6,4(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4+2π/3)+2eT5COS(T6-2π/3))]/6 =[exp(-t1+t2-t3+t4-t5)+exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2+2π/3) +2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)/2-2π/3)]/6
S6,5(t1,t2,t3,t4,t5) =[eT1+eT2-2eT3COS(T4-2π/3)+2eT5COS(T6)-π/3]/6 =[exp(-t1+t2-t3+t4-t5)-exp(t1+t2+t3+t4+t5) +2exp((t1-t2-2t3-t4+t5)/2)COS((t1+t2-t4-t5)/2-2π/3) +2exp((-t1-t2-2t3-t4-t5)/2)COS((t1-t2+t4-t5)/2-π/3)]/6

亦即为:
S6,0(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4)+2eT5COS(T6)]/6
S6,1(t1,t2,t3,t4,t5) =[eT1-eT2+2eT3COS(T4+2π/3)+2eT5COS(T6)π/3]/6
S6,2(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4-2π/3)+2eT5COS(T6+2π/3)]/6
S6,3(t1,t2,t3,t4,t5) =[eT1-eT2+2eT3COS(T4)-2eT5COS(T6)]/6
S6,4(t1,t2,t3,t4,t5) =[eT1+eT2+2eT3COS(T4+2π/3)+2eT5COS(T6-2π/3))]/6
S6,5(t1,t2,t3,t4,t5) =[eT1+eT2-2eT3COS(T4-2π/3)+2eT5COS(T6)-π/3]/6
T1=-t1+t2-t3+t4-t5 T2=t1+t2+t3+t4+t5 T3=t1-t2-2t3-t4+t5)/2 T4=(t1+t2-t4-t5)/2 T5=(-t1-t2-2t3-t4-t5)/2 T6=(t1-t2+t4-t5)/2

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